Expert Answers

(Solved): Calculate the molarity of 74.0 gl of glucose in 1.50 L of a ...

Calculate the molarity of 74.0 gl of glucose in 1.50 L of a glucose solution.

(Solved): CASE STUDY 12.3 A 45-year-old man has been a paraplegic sinc...

CASE STUDY 12.3 A 45-year-old man has been a paraplegic since being involved in a motorcycle accident 20 years ago. He has a history of recurrent urinary tract infections. (UTIs) as a result of infection from an indwelling catheter. He now has severe back pain, with fever, chills, and vomiting. He has been exposed to "the flu" and seeks medical attention. A midstream urine specimen is collected for examination and culture. The following routine urinalysis results were obtained: Physical Appearance Color: Yellow Transparency: Cloudy Chemical Screening pH: 6.5 Specific gravity: 1.010 Protein (reagent strip):

100m(g)/(d)L

Blood: Moderate Nitrite: Negative Leukocyte esterase: Positive Glucose: Negative Ketones: Negative Bilirubin: Negative Urobilinogen: Normal Microscopic Examination RBCs: 2-5/hpf WBCs: 10-25/hpf Casts: 5-10 WBC casts/lpf Bacteria: Moderate rods Multiple Choice Questions (Answers are in Appendix A) This patient's proteinuria is probably caused by which of the following? a. Glomerular damage b. Lower urinary tract disorder c. Prerenal disorder d. Tubular (or interstitial) damage Concerning the positive leukocyte esterase and the negative nitrite in this patient, which of the following statements is correct? a. The leukocyte esterase test is probably a false-positive reaction. b. The negative nitrite reaction is probably caused by insensitivity of the test or lack of sufficient incubation of urine in the bladder. c. The positive leukocyte esterase reaction indicates that an upper UTI is present, d. The presence of a bacterial infection is ruled out because of the negative nitrite reaction. Concerning the positive reagent strip test for blood and the relatively low level of RBCs seen in the urine sediment of this patient, which of the following statements is correct? a. The presence of hematuria is not consistent with the disease exhibited by this patient. b. The presence of protein is probably interfering with the chemical test for blood. c. The reagent strip test is extremely sensitive and consistent with the microscopic findings. d. The reagent strip test is probably falsely positive because of the presence of ascorbic acid.

(Solved): An ideal gas at 16.5\deg C and a pressure of 2.28\times 10^(...

An ideal gas at

16.5\deg C

and a pressure of

2.28\times 10^(5)Pa

occupies a volume of

2.77m^(3)

. (a) How many moles of gas are present? (b) If the volume is raised to

4.02m^(3)

and the temperature raised to

27.1\deg C

, what will be the pressure of the gas? (a) Number

Units

(b) Number

Units

student submitted image, transcription available below

(Solved): (TRUE/FALSE) Enteric pathogens (Enterobacteriaceae) are the ...

(TRUE/FALSE) Enteric pathogens (Enterobacteriaceae) are the most frequent cause of diarrheal illness, causing up to 3 million deaths & 4 billion infections worldwide each year. Select one: True False

student submitted image, transcription available below

(Solved): A 2 kg block is held at rest some distance h above the top o...

A 2 kg block is held at rest some distance

h

above the top of a vertical spring. The block is dropped and lands on the spring, compressing it to a maximum of 0.31 meters. How high above the spring was the block held (i.e., what is

h

)? The spring constant

k=450(N)/(m)

. (A) 1.10 m B) 2.42 m

m=2kg

h=2

D) 1.68 m

h=2.31m

/bar (k_(i))+(\Pi )/(v_(9))+

(+)/(b)ar (u_(si))(+)/(b)ar (w)()/(b)=ar (k_(f))(+)/(b)ar (v_(gf))+(◻)/(u_(sf))

. E) 2.03 m System: Block, Earth, Spring Initial: At rest, stationary

mgh=(1)/(2)kd^(2)

h=1.10m

h=((1)/(2)kd^(2))/(mg)

Final: moving, spring Ccme

h=((1)/(2)(450)(0.31)^(2))/((2)(9.8))

(Solved): I need help understanding how I would fill this out. The que...

I need help understanding how I would fill this out. The questions ask: In this matrix, there are three species of organisms from the Allurian community: boreblasters, spotted gliders, and umbrella trees. The following information is needed to help me fill out the matrix table: BOREBLASTERS: Habitat This species is strictly terrestrial, and in its larval stage it lives in an entirely covered environment burrowing through the woody tissue of plant flora, such as Umbrella trees. However, once they reach maturation and metamorphose into either their breeding or migratory morph, they leave the shelter. Diet Boreblasters consume the woody vegetation and the fruits of umbrella trees. The larvae depend on umbrella trees for food and shelter. Adults do not feed, because the mouth parts fuse during metamorphosis. Interesting Fact Boreblasters produce a toxin that is poisonous to most species. Few predators in the Allurian Forest can tolerate the toxin well enough to consume the eggs or larvae, which have high concentrations of toxin. SPOTTED GLIDER: Diet Spotted gliders are omnivores, consuming the fruit from umbrella trees and larval boreblasters. UMBRELLA TREE: Diet Umbrella trees are autotrophic, absorbing radiation through the large, cup-like structures that cover them and exchanging natural gases with the environment through their trunks to produce their own energy. Interesting Fact Fruits of the umbrella tree, while appealing to some creatures of Alluria, are toxic to humans. Upon consumption of these fruits, a human would have about an hour before they began to feel symptoms such as rashes, extreme fevers, and possible anaphylaxis. Please let me know if you need further information, TIA

(Solved): The electron drift speed in a 1.50-mmmm-diameter gold wire i...

The electron drift speed in a 1.50-mmmm-diameter gold wire is 3.50 ×× 10−5−5 m/sm/s.

(Solved): 1. Which selection tests are useful in predicting perf...

1. Which selection tests are useful in predicting performance one year later? Please indicate below the selection tests (Personality Test, Competency Interview [Assessment Center] Test, Aptitude Test) that are most helpful in predicting performance one year later. What criteria did you use to select your answer? 2. Does personality matter for predicting performance one year later? If yes, which specific personality traits are likely to predict performance? What criteria did you use to select these personality traits? Note that the personality test used at the time of selection measures 5 different personality traits: openness, conscientiousness, extraversion, agreeableness, and neuroticism. 3. The VP of HR is also concerned about the costs of conducting aptitude tests. Presently the selection process includes 2 different aptitude tests: one for numerical reasoning and one for verbal reasoning. Do both aptitude tests predict performance one year later? If the company had to save costs by dropping one aptitude test, which one would you recommend dropping? Why? 4. Is the money spent on induction programs worth it? Does the induction program have a meaningful effect on performance? Why/Why not?

(Solved): Let A=[[-4,2,8],[2,-7,4],[8,4,8]]. The eigenvalues of the re...

Let A=[[-4,2,8],[2,-7,4],[8,4,8]]. The eigenvalues of the real symmetric matrix A are \lambda _(1)=13 and \lambda _(2)=-8. An orthonormal basis for the eigenspace for \lambda _(1)=13 is B_(1)={u_(1)} where u_(1)=[[,|],[,|]] and an orthonormal basis for the eigenspace for \lambda _(2)=-8 is B_(2)={u_(2),u_(3)} where u_(2)=[[,|],[,|]],u_(3)=[]

(Solved): Evaluate the indefinite integral. (Use C for the constant of...

Evaluate the indefinite integral. (Use C for the constant of integration.)

\int (e^(u))/((3-e^(u))^(2))du
student submitted image, transcription available below