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(Solved): A different galaxy cluster has galaxies within it whose disp...

A different galaxy cluster has galaxies within it whose dispersion in redshift (about their mean redshift) is found from spectroscopic observations to be σz. The mean redshift of all the galaxies is . Observing the locations of the galaxies in this cluster, we find that the half-light radius (the radius that encloses half of all the light from the galaxies in the cluster) subtends an angle of θh. What is the estimated mass of this galaxy cluster? Give your response in solar masses, in scientific notation to one decimal place. (You can assume the peculiar velocity of the cluster as a whole is negligible, i.e. the cluster's mean redshift is obtained with the Hubble flow). Hints: As in our video, you can take the geometric factor to be α = 0.45. Also, don't miss the factor of 3 between the line-of-sight velocity dispersion and the total velocity dispersion (do you understand where this factor of 3 comes from?). Values: = 0.1 σz = 0.004 θh = 14 arcminutes

(Solved): balance the molecular equation: (NH4)3PO4+Zn(NO3)2->Zn3(P...

balance the molecular equation: (NH4)3PO4+Zn(NO3)2->Zn3(PO4)2+NH4NO3

(Solved): Gary Stevens and Mary James are production managers in the C...

Gary Stevens and Mary James are production managers in the Consumer Electronics Division of General Electronics Company, which has several dozen plants scattered throughout the world. Mary manages the plant located in Des Moines, Iowa, while Gary manages the plant in El Segundo, California. Production managers are paid a salary plus a bonus equal to 10% of their base salary if the entire division meets or exceeds its target profits for the year. The bonus is determined in March after the company’s annual report has been prepared and issued to stockholders. Shortly after the beginning of the new year, Mary received a phone call from Gary that went like this: Gary:I just got the preliminary profit figures for the division for last year and we are within $65,200 of making the year’s target profits. All we have to do is pull a few strings, and we’ll be over the top!Mary:What do you mean?Gary:Well, one thing that would be easy to change is your estimate of the percentage completion of your ending work in process inventories.Mary:I don’t know if I can do that, Gary. Those percentage completion figures are supplied by Tom Winthrop, my lead supervisor, who I have always trusted to provide us with good estimates. Besides, I have already sent the percentage completion figures to corporate headquarters.Gary:You can always tell them there was a mistake. Think about it, Mary. All of us managers are doing as much as we can to pull this bonus out of the hat. You may not want the bonus check, but the rest of us sure could use it. The final processing department in Mary’s production facility began the year with no work in process inventory. During the year, 350,000 units were transferred in from the prior processing department and 326,000 units were completed and sold. Costs transferred in from the prior department totaled $86,800,000. No materials are added in the final processing department. A total of $23,240,000 of conversion cost was incurred in the final processing department during the year. Required: Tom Winthrop estimated the units in ending work in process inventory in the final processing department were 25% complete for conversion costs. If this estimate of the percentage completion is used, what would be the cost of goods sold for the year? Does Gary Stevens want the estimated percentage completion to be increased or decreased? What percentage completion would increase net operating income by $65,200 over the net operating income based on Winthrop’s original estimates? Tom Winthrop estimated the units in ending work in process inventory in the final processing department were 25% complete for conversion costs. If this estimate of the percentage completion is used, what would be the cost of goods sold for the year? What percentage completion would increase net operating income by $65,200 over the net operating income based on Winthrop’s original estimates? Note: Round cost per unit to 2 decimal places. Do not round other intermediate calculations. Round your final answer to 2 decimal places.

(Solved): During SARS-CnV-2 infantina the activation of epithelial cel...

During SARS-CnV-2 infantina the activation of epithelial cells and local immune coll via PRRs leads to the production of cytokines, with the influx of fluid and leukocytes. proinflammatory: more anti-inflammatory; fewer proinflammatory; fewer anti-inflammatory. more

(Solved): A 37.4-mL sample of H_(2) at STP would contain how many gram...

A 37.4-mL sample of

H_(2)

at STP would contain how many grams of hydrogen? 0.0864 g 0.00337 g 1.45 g 5.67 g 45.7 g

student submitted image, transcription available below

(Solved): Learning Goal: To calculate the shear stress at the web/flan...

Learning Goal: To calculate the shear stress at the web/flange joint in a beam and use that stress to calculate the required nail spacing to make a built-up beam. A built up beam can be constructed by fastening flat plates together. When an I-beam is subjected to a shear load, internal shear stress is developed at every cross section, with longitudinal shear stress balancing transverse shear stress. If the beam is built up using plates, the fasteners used must be able to resist the shear at the joints. The loading resisted by the fasteners can be described in the force per unit length of the beam and is called the shear flow. The shear flow at some distance

y

from the neutral axis can be calculated using the shear formula

q=(VQ)/(I)

, where

V

is the shear force,

Q

is the moment about the centroidal axis of the cross-sectional area above

y

, and

I

is the moment of inertia of the cross section. An engineered wood beam (Figure 1) will replace a portion of a structural wall as part of a house renovation. The beam can be modeled as a simply supported beam with a span

L=11

ft and an uniform distributed load

w=825l(b)/(f)t

. The beam is to be constructed as an l-beam with nails securing the flanges to the web. The flanges are 6 in wide and 1 in thick. The web has depth 18 in and thickness 3 in . The maximum allowable shear stress in the web is 900 psi. Part A - Maximum shear load Assuming the joints do not fail, what is the maximum shear load the beam can support? Express your answer with appropriate units to three significant figures. View Available Hint(s)

Previous Answers Incorrect; Try Again; 5 attempts remaining Part B - Shear flow at joint What is the maximum shear flow at the joints connecting the web and flange under the applied load of

w=825l(b)/(f)t

? Express your answer with appropriate units to three significant figures. View Available Hint(s)

Part C - Maximum nail spacing Since the nails are joining the flanges to the web, they must resist the shear flow at the joint. What is the maximum spacing for the nails if each nail can support a shear force of 250 lb ? Express your answer with appropriate units to three significant figures. View Available Hint(s)

student submitted image, transcription available below

(Solved): Question 9 (1 point) , saved Listen Stress suppresses the im...

Question 9 (1 point)

,✓

saved Listen Stress suppresses the immune system, thus making it easier for you to become sick from viruses and bacteria.

True

False

(Solved): When a support worker is faced with an ethical dilemma, whic...

When a support worker is faced with an ethical dilemma, which of the following questions should they ask themselves in order to decide on a course of action?

(Solved): briefly summarize the sources of workplace discrimination an...

briefly summarize the sources of workplace discrimination and health among filipinos in the united states

(Solved): Identify which sets of quantum numbers are valid for an elec...

Identify which sets of quantum numbers are valid for an electron. Each set is ordered (n,ℓ,mℓ,msn,ℓ,mℓ,ms). Check all that apply. View Available Hint(s)for Part A 2,3,1,1/22,1,-1,1/21,2,0,1/23,3,-1,1/23,2,-2,1/22,-1,1,-1/22,1,-1,-1/24,3,4,-1/23,2,1,14,3,3,-1/23,0,0,1/20,1,1,-1/2