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(Solved): For the reaction 4PH36H2(g)+P4(g) The equilibrium concentrations were found to be [PH3]=0.250 M, ...



For the reaction 4PH3↔6H2(g)+P4(g) The equilibrium concentrations were found to be [PH3]=0.250 M, [H2]=0.420 M, and [P4]=0.750 M. What is the equilibrium constant for this reaction



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