Find the dimensions of a rectangle with perimeter 112 m whose area is as large as possible. Part 1 of 4 If a rectangle has dimensions x and y, then we must maximize the area A = xy. Since the perimeter is 2x + 2y = 112, then y = x.

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Find the dimensions of a rectangle with perimeter 112 m whose area is as large as possible.  Part 1 of 4  If a rectangle has dimensions x and y, then we must maximize the area  A = xy.   Since the perimeter is  2x + 2y = 112,  then  y =  x.

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