A 2 kg block is held at rest some distance
h
above the top of a vertical spring. The block is dropped and lands on the spring, compressing it to a maximum of 0.31 meters. How high above the spring was the block held (i.e., what is
h
)? The spring constant
k=450(N)/(m)
. (A) 1.10 m B) 2.42 m
m=2kg
h=2
D) 1.68 m
h=2.31m
/bar (k_(i))+(\Pi )/(v_(9))+
(+)/(b)ar (u_(si))(+)/(b)ar (w)()/(b)=ar (k_(f))(+)/(b)ar (v_(gf))+(◻)/(u_(sf))
. E) 2.03 m System: Block, Earth, Spring Initial: At rest, stationary
mgh=(1)/(2)kd^(2)
h=1.10m
h=((1)/(2)kd^(2))/(mg)
Final: moving, spring Ccme
h=((1)/(2)(450)(0.31)^(2))/((2)(9.8))