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(Solved): A 2 kg block is held at rest some distance h above the top of a vertical spring. The block is droppe ...



A 2 kg block is held at rest some distance

h

above the top of a vertical spring. The block is dropped and lands on the spring, compressing it to a maximum of 0.31 meters. How high above the spring was the block held (i.e., what is

h

)? The spring constant

k=450(N)/(m)

. (A) 1.10 m B) 2.42 m

m=2kg

h=2

D) 1.68 m

h=2.31m

/bar (k_(i))+(\Pi )/(v_(9))+

(+)/(b)ar (u_(si))(+)/(b)ar (w)()/(b)=ar (k_(f))(+)/(b)ar (v_(gf))+(◻)/(u_(sf))

. E) 2.03 m System: Block, Earth, Spring Initial: At rest, stationary

mgh=(1)/(2)kd^(2)

h=1.10m

h=((1)/(2)kd^(2))/(mg)

Final: moving, spring Ccme

h=((1)/(2)(450)(0.31)^(2))/((2)(9.8))


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